University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 42 - Molecules and Condensed Matter - Problems - Exercises - Page 1435: 42.21

Answer

$1.5\times10^{22}\;states/eV$.

Work Step by Step

The density of states is calculated by equation 42.15, $g(E)=\frac{(2m)^{3/2}V}{2\pi^2\hbar^3}E^{1/2}$. Convert the given energy to $1.12\times10^{-18}J$ and the volume to $1.0\times10^{-6}m^3$, and evaluate using the electron mass to find $g(E)=1.5\times10^{22}\;states/eV$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.