University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 41 - Quantum Mechanics II: Atomic Structure - Problems - Exercises - Page 1403: 41.26

Answer

a. The letter is g. b. $2.90\times 10^{-7}eV$.

Work Step by Step

a. The $j$ quantum number takes the values $l+\frac{1}{2}$ and $l-\frac{1}{2}$. If j has the values 7/2=3.5 and 9/2=4.5, it must be that $l=4$. The letter that labels this value is g. b. Equation 41.41 gives the energy of each energy level. Calculate the energy for n = 5, using j = 7/2 and then j = 9/2, and subtract the values. The energy difference is $2.90\times10^{-7}eV$.
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