University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 37 - Relativity - Problems - Exercises - Page 1249: 37.37

Answer

See explanation.

Work Step by Step

a. Express the total energy in terms of the given momentum and known rest mass. $$E=\sqrt{(mc^2)^2+(pc)^2}=8.68\times10^{-10}J$$ b. The kinetic energy is the total energy minus the rest energy. $$K=8.68\times10^{-10}J –mc^2=2.71\times10^{-10}J $$ c. $\frac{K}{mc^2}=0.453$.
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