Answer
See explanation.
Work Step by Step
Apply the work energy theorem. $W=\Delta K$.
$\gamma=\frac{1}{\sqrt{1-v^{2}/c^{2}}}$
The relativistic kinetic energy is $(\gamma-1)mc^2$.
$\gamma_i=1$ when the object is at rest.
a. $W=\Delta K = (\gamma_f-\gamma_i)mc^2=(4.07\times10^{-3})mc^2$
b. $W=\Delta K = (\gamma_f-\gamma_i)mc^2=(7.0888-2.2942)mc^2=4.79mc^2$
c. The result of part B is much larger than that of part A. The work required to produce a given increase in speed increases as the initial speed becomes larger.
