Answer
See explanation.
Work Step by Step
a. This is nonrelativistic. F = ma.
$$a=\frac{F}{m}=5.49\times10^{15}m/s^2$$
b. According to equation 37.32, in this situation, the force is $F=\gamma^3 ma$.
The value of $\gamma$ is $\frac{1}{\sqrt{1-v^{2}/c^{2}}}=1.81$.
$$a=\frac{F}{m \gamma^3}=9.27\times10^{14}m/s^2$$
