University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 37 - Relativity - Problems - Exercises - Page 1249: 37.26

Answer

See explanation.

Work Step by Step

According to equation 37.32, in this situation, the force is $F=\gamma^3 ma$. a. Essentially the same as ma = 0.145N. b. $F=\gamma^3 ma=1.75N$ c. $F=\gamma^3 ma=51.7N$ According to equation 37.33, in this situation, the force is $F=\gamma ma$. d. $F=\gamma ma=0.145N, 0.333N, 1.03 N$
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