University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Exercises - Page 1213: 36.42


195 m.

Work Step by Step

The angular size of the object is $ \theta=\frac{1.40\times10^8m}{4.3(9.461\times10^{15}m)}=3.44\times10^{-9}rad$. Use Rayleigh’s criterion to find the resolution. The resolving power is $ \theta_{r}=1.22\frac{\lambda}{D}$. $$3.44\times10^{-9}rad =1.22\frac{\lambda}{ D}$$ $$D =1.22\frac{550\times10^{-9}m }{3.44\times10^{-9}rad }=195m$$
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