University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Exercises - Page 1213: 36.41


220 m.

Work Step by Step

The diameter D of the telescope determines the resolution. The resolving power is $ \theta_{r}=1.22\frac{\lambda}{D}$. We are told that the resolving powers are to be identical. $$\frac{\lambda_1}{D_1}=\frac{\lambda_2}{D_2}$$ $$D_2=D_1 \frac{\lambda_2}{\lambda_1}=(8000000m)\frac{550\times10^{-9}m 2}{2.0\times10^{-2}m }=220m$$
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