University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Exercises - Page 1213: 36.26

Answer

$20.2^{\circ}$.

Work Step by Step

The maxima are located by $d sin \theta = m \lambda$. The order is the value of m. $$d=\frac{m\lambda}{sin \theta}$$ $$d=\frac{3 (700 \times10^{-9}m)}{sin 65.0^{\circ}}=2.317\times 10^{-6}m$$ Now find the angle desired. $$d=2.317\times 10^{-6}m =\frac{2(400 \times10^{-9}m)}{sin \theta_v}$$ $$ sin \theta_v =\frac{2(400 \times10^{-9}m)}{2.317\times 10^{-6}m}=0.3453$$ $$ \theta_v =20.2^{\circ}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.