University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Exercises - Page 1213: 36.40


2.3 mm.

Work Step by Step

Use Rayleigh’s criterion, $sin \theta_1=1.22\frac{\lambda}{D}$. $$D =1.22\frac{\lambda}{ sin \theta_1}$$ $$D =1.22\frac{550\times10^{-9}m }{ sin (1/60)^{\circ}}=2.3\times10^{-3}m$$
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