Answer
2.3 mm.
Work Step by Step
Use Rayleigh’s criterion, $sin \theta_1=1.22\frac{\lambda}{D}$.
$$D =1.22\frac{\lambda}{ sin \theta_1}$$
$$D =1.22\frac{550\times10^{-9}m }{ sin (1/60)^{\circ}}=2.3\times10^{-3}m$$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 36 - Diffraction - Problems - Exercises - Page 1213: 36.40
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