#### Answer

a.) $33.542m \\ $
b.) $15.7\frac{m}{s} \\ $
c.)
Blue: acceleration vs time
Red: velocity vs time
Gray: position vs time

#### Work Step by Step

Taking the vertical axis up as positive and the surface of mars as $y=0$
Mars gravity: $g_{m} = 0.379g = 0.379\cdot 9.8\frac{m}{s^2} = 3.7142\frac{m}{s^2}$
Time of flight: $t_f = 8,5s$
The tennis ball gets to its maximum height at half of the time of flight. That is $t_{max\ h} = \dfrac{t_f}{2} = \dfrac{8.5s}{2} = 4.25s$
When the tennis ball gets to its maximum height, its velocity will be $0$. That means that $v$ at $t=4.25s$ equals $0$
Therefore we can find how fast was it moving just after it was hit, which is its initial velocity ($v_o$):
$$
v_{t=4.25s} = v_o + g_m\cdot t_{max\ h} \\
0 = v_o - 3.7142\frac{m}{s^2} \cdot 4.25s = v_o - 15.785\frac{m}{s} \\
v_o = 15.785\frac{m}{s}
$$
Now we can find how high above its original point did the ball go, that is the maximum height ($y_{max}$):
$$
y_{max} = y_o + v_o\cdot t_{max\ h}+0.5\cdot g_m\cdot (t_{max\ h})^2 \\
= 0 + 15.785\cdot4.25s + 0.5\cdot (-3.7142)\cdot (4.25)^2 \\
= 67.086-33.544 = 33.542m
$$