## University Physics with Modern Physics (14th Edition)

The putty has a constant downward acceleration. We know the initial velocity of 9.50 m/s and the displacement of 3.60 m. Use the kinematics formulas for constant acceleration. a. $v_f^2=v_o^2+2a(\Delta x)$ $v_f^2=(9.50m/s)^2+2(-9.80m/s^2)(3.60m)$ $v_f=4/44 m/s$ b. $t = \frac{v_y-v_{oy}}{a_y}=\frac{4.437m/s-9.50m/s}{-9.80m/s^2}=0.517s$