University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 61: 2.35


(a) v = 2.94 m/s (b) t = 0.600 s

Work Step by Step

(a) When the flea reaches its maximum height, then the velocity v = 0 m/s. $v^2 = v_0^2 + 2ay$ $v_0^2 = 0 - 2ay$ $v_0 = \sqrt{-2ay} = \sqrt{-(2)(-9.80 ~m/s^2)(0.440 ~m)}$ $v_0 = 2.94~m/s$ (b) We can find the time $t$ to reach maximum height. $t = \frac{v-v_0}{a} = \frac{0-2.94~m/s}{-9.80~m/s^2}$ $t = 0.300~s$ The total time in the air is 2t = (2)(0.300 s), which is 0.600 seconds.
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