# Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 61: 2.37

The total time is 1.67 seconds.

#### Work Step by Step

We can find the time $t$ for the bowling pin to reach maximum height. Note that v = 0 m/s at maximum height. $t = \frac{v-v_0}{a} = \frac{0-8.20~m/s}{-9.80~m/s^2}$ $t = 0.8367~s$ The total time for the bowling pin to reach maximum height and fall back down to the juggler's hand is $2t$. $2t = (2)(0.8367~s) = 1.67~s$ The total time is 1.67 seconds.

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