Answer
(a) $T = 0.167~s$
(b) $\omega = 37.7~rad/s$
(c) $m = 84.4~g$
Work Step by Step
(a) We can find the period of the motion.
$T = \frac{1}{f}$
$T = \frac{1}{6.00~Hz}$
$T = 0.167~s$
(b) We can find the angular frequency.
$\omega = 2\pi~f$
$\omega = (2\pi)(6.00~Hz)$
$\omega = 37.7~rad/s$
(c) We can find the mass $m$.
$\omega^2 = \frac{k}{m}$
$m = \frac{k}{\omega^2}$
$m = \frac{120~N/m}{(37.7~rad/s)^2}$
$m = 0.0844~kg = 84.4~g$
