Answer
(a) $T = 0.0667~s$
(b) $f = 15.0~Hz$
(c) $\omega = 94.2~rad/s$
Work Step by Step
(a) We can find the period of the motion.
$T = \frac{60~s}{900~cycles}$
$T = 0.0667~s$
(b) We can find the frequency of the motion.
$f = \frac{1}{T} = \frac{1}{0.0667~s} = 15.0~Hz$
(c) We can find the angular frequency.
$\omega = 2\pi~f$
$\omega = (2\pi)(15.0~Hz)$
$\omega = 94.2~rad/s$
