Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 315: 6-53E

Answer

$n=2$

Work Step by Step

$\dot{Q}_c=8.4\ kW\times0.4=3.36\ kW$ $\dot{Q}_p=7\times100W=0.7\ kW$ $\dot{Q}=4.06\ kW=13853\ Btu/h$ $n=\dot{Q}/\dot{Q}_u,\ \dot{Q}_u=7000\ Btu/h$ $n=1.98\rightarrow n=2$
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