Answer
$\dot{W}_i=0.40\ kW$
Work Step by Step
Total heat removal rate:
$\dot{Q}_L=4\times800\ kJ/h=3200\ kJ/h$
$COP_R=\dot{Q}_L/\dot{W}_i=2.2$
$\dot{W}_i=1455\ kJ/h=0.40\ kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 315: 6-51
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