Answer
$\dot{W}_i=0.775\ hp$
Work Step by Step
$\dot{Q}_L=\dot{m}q$
Given $q=169\ Btu/lbm,\ \dot{m}=28\ lbm/h$
$\dot{Q}_L=4732\ Btu/h$
$COP_R=\dot{Q}_L/\dot{W}_i=2.4$
$\dot{W}_i=1971.67\ Btu/h=0.775\ hp$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 315: 6-50E
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