Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 271: 5-187

Answer

a) $T_4=108.6°C$ b) $\dot{V}=0.0449\ m^3/s$

Work Step by Step

For the turbine: $\dot{m}_gh_1=\dot{m}_gh_2+\dot{W}_s$ $\dot{W}_s=\dot{m}_gc_p(T_1-T_2)$ $\dot{m}_g=0.02\ kg/s,\ c_p=1.063\ kJ/kg.°C,\ T_1=400\ K,\ T_2=350\ K$ $\dot{W}_s=1.063\ kW$ input to the compressor For the compressor: $\dot{W}_s+\dot{m}_ah_3=\dot{m}_ah_4$ $\dot{W}_s=\dot{m}_ac_p(T_4-T_3)$ $\dot{m}_a=0.018\ kg/s,\ c_p=1.008\ kJ/kg.K,\ T_3=50°C$ $T_4=108.6°C$ For the aftercooler: $\dot{m}_cc_{p,c}(T_{c,e}-T_{c,i})=\dot{m}_ac_{p,a}(T_4-T_5)$ $c_{p,c}=1.005\ kJ/kg.°C,\ T_{c,e}=40°C,\ T_{c,i}=30°C,\ T_5=80°C$ $\dot{m}_c=0.05161\ kg/s$ $\dot{m}=\frac{P\dot{V}}{RT}$ For the cold air inlet: $P=100\ kPa,\ R=0.287\ kJ/kg.K,\ T=30°C$ $\dot{V}=0.0449\ m^3/s$
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