Answer
$W_{b,i}=P_2(V_1-V_2)=27.9\ kJ$
$T_2=415.0\ K$
$m_e=0.262\ kg$
Work Step by Step
$PV=mRT,\ R=0.287\ kJ/kg.K$
$m_1=1.2\ kg,\ T_1=473\ K,\ P_1=700\ kPa$
$V_1=0.2327\ m^3$
$V_2=0.80V_1=0.1862\ m^3$
$T_2=?,\ P_2=600\ kPa\ rightarrow m_2=389.18/T_2$
Constant pressure: $W_b=P_2(V_1-V_2)=27.9\ kJ$
$-m_e=m_2-m_1$
$W_b-Q-m_eh_e=m_2u_2-m_1u_1,\ Q=40\ kJ$
$W_b-Q-(m_1-m_2)c_pT_e=m_2c_vT_2-m_1c_vT_1,\quad T_e=0.5(T_1+T_2)$
$-0.5(m_1-m_2)c_p(T_1+T_2)=m_2c_vT_2-m_1c_vT_1-W_b+Q$
$c_p=1.005\ kJ/kg.K,\ c_v=0.718\ kJ/kg.K$
Solving for $T_2=415.0\ K$
$m_2=0.938\ kg$
$m_e=0.262\ kg$
