Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 271: 5-186

Answer

a) $T_2=179.9°C$, $\dot{W}_s=1616\ kW$ b) $T_2=151.8°C,\ \dot{W}_s=2134\ kW$ c) $T_2=99.6°C,\ \dot{W}_s=2333\ kW$ d) $T_2=81.3°C,\ \dot{W}_s=2173\ kW$

Work Step by Step

From table A-6: Flash inlet ($x_1=0, T_1=230°C$): $h_1=990.14\ kJ/kg$ Sep.inlet ($P_2=1\ MPa, h_2=h_1$): $x_2=0.113,\ T_2=179.9°C$ Turb. inlet ($P_3=1\ MPa, x_3=1$): $h_3=2777.1\ kJ/kg$ Turb. outlet ($P_4=20\ kPa, x_4=0.95$): $h_4=2491.1\ kJ/kg$ $\dot{m}_3=x_2\dot{m}_1,\ \dot{m}_1=50\ kg/s$ $\dot{m}_3=5.649\ kg/s$ $\dot{W}_s=\dot{m}_3(h_3-h_4)$ $\dot{W}_s=1616\ kW$ Repeating the procedure for: $P_2=500\ kPa$: $T_2=151.8°C,\ \dot{W}_s=2134\ kW$ $P_2=100\ kPa$: $T_2=99.6°C,\ \dot{W}_s=2333\ kW$ $P_2=50\ kPa$: $T_2=81.3°C,\ \dot{W}_s=2173\ kW$
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