Answer
$W_{b,i}=11.6\ kJ$
$Q_e=60.7\ kJ$
Work Step by Step
From table A-13:
Initial ($P_1=0.8\ MPa, T_1=80°C$): $v_1=0.032659\ m³/kg,\ u_1=290.86\ kJ/kg,\ h_1=316.99\ kJ/kg$
Final ($P_2=0.5\ MPa, T_2=20°C$): $v_2=0.042115\ m³/kg,\ u_2=242.42\ kJ/kg,\ h_2=263.48\ kJ/kg$
$m_1=2\ kg,\ m_2=m_1/2=1\ kg$
$-m_e=m_2-m_1,\rightarrow m_e=1\ kg $
$V=mv$
$V_1=0.06532\ m^3,\ V_2=0.04212\ m^3$
$h_e=\frac{h_1+h_2}2=290.23\ kJ/kg$
Constant pressure: $W_b=P(V_1-V_2),\ P=500\ kPa \rightarrow W_b=11.6\ kJ$
$W_b-Q-m_eh_e=m_2u_2-m_1u_1$
$Q=60.7\ kJ$
