Answer
$Q_i=2308\ kJ$
Work Step by Step
From tables A-4 to A-6:
Initial ($x_1=0, T_1=200°C$): $v_1=0.001157\ m³/kg,\ u_1=850.46\ kJ/kg$
Exiting ($x_e=0, T_e=200°C$): $h_e=852.26\ kJ/kg$
From $m=V/v,\ V_t=0.3\ m³$:
$m_1=259.4\ kg$
Since $m_2=1/2\times m_1 \rightarrow m_2=129.7\ kg$
From the material balance:
$m_e=m_1-m_2$
$m_e=129.7\ kg$
Hence $v_2=0.002313\ m³/kg$
Final state ($T_2=200°C,\ v_2$): $x_2=0.009171,\ u_2=866.46\ kJ/kg$
From the energy balance:
$Q_i-m_eh_e=m_2u_2-m_1u_1$
$Q_i=2308\ kJ$
