Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 263: 5-122

Answer

$m_i=64.82\ kg$ $Q_i=627\ kJ$

Work Step by Step

From tables A-11 to A-13: Initial ($P_1=0.8\ MPa, x_1=1$): $v_1=0.02565\ m³/kg,\ u_1=246.82\ kJ/kg$ Final ($P_2=1.2\ MPa, x_2=0$): $v_2=0.0008935\ m³/kg,\ u_2=116.72\ kJ/kg$ Entering ($P_i=1.2\ MPa, T_i=36°C$): $h_i=102.34\ kJ/kg$ From $m=V/v,\ V_t=0.06\ m³$: $m_1=2.340\ kg,\ m_2=67.16\ kg$ From the material balance: $m_i=m_2-m_1$ $m_i=64.82\ kg$ From the energy balance: $Q_i+m_ih_i=m_2u_2-m_1u_1$ $Q_i=627\ kJ$
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