Answer
a) $T_2=120.2°C$
b) $m_i=19.07\ kg$
Work Step by Step
From tables A-4 to A-6:
Initial ($P_1=200\ kPa, x_1=0.6$): $h_1=1825.6\ kJ/kg$
Final ($P_2=200\ kPa, x_2=1$): $h_2=2706.3.3\ kJ/kg$
Entering ($P_i=0.5\ MPa, T_i=350°C$): $h_i=3168.1\ kJ/kg$
$T_2=T_{sat}=120.2°C$
From the material balance:
$m_i=m_2-m_1$
From the energy balance:
$m_ih_i=W_{b,e}+m_2u_2-m_1u_1$
$(m_2-m_1)h_i=m_2h_2-m_1h_1$
Since $m_1=10\ kg$:
solving for the final mass $m_2=29.07\ kg$
Hence $m_i=19.07\ kg$
