Answer
$T_2=48.9°C$
Work Step by Step
From table A-12:
Inlet ($P_1=180\ kPa$, sat. liquid): $v_1=0.1105\ m³/kg,\ h_1=242.9\ kJ/kg$
The mass flowrate is given by (with $\dot{V}_1=0.35\ m³/min$):
$\dot{V}_1=\dot{m}v_1$
$\dot{m}=0.05283\ kg/s$
From the energy balance:
$\dot{W}_s+\dot{m}h_1=\dot{m}h_2$
Hence, with $\dot{W}_s=2.35\ kW$, $h_2=287.41\ kJ/kg$
From table A-13:
Outlet ($P_2=700\ kPa,\ h_2$): $T_2=48.9°C$
