Answer
$T_2=466\ K= 193°C$
Work Step by Step
For a polytropic process on an ideal gas, we have:
$(\frac{T_2}{T_1})^n=(\frac{P_2}{P_1})^{(n-1)}$
Given $T_1=673\ K, P_2=110\ kPa, P_1=1000\ kPa, n=1.2$
we get to: $T_2=466\ K= 193°C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 205: 4-110
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