Answer
i) $V_2=120\ m/s$
ii) $z_2=732\ m$
Work Step by Step
The change in specific internal energy of air (with $c_v=0.718\ kJ/kg.K, \Delta T=10\ K$):
$\Delta u=c_v\Delta T$
$\Delta u = 7.18\ kJ/kg=7180\ J/kg$
i) If $\Delta u=\Delta ke$:
$1/2\times(V_2^2-0^2)=7180 J/kg\rightarrow V_2=120\ m/s$
ii) If $\Delta u=\Delta pe$, (with $g=9.81 m/s²$):
$g(z_2-0)=7180\ J/kg\ \rightarrow z_2=732\ m$
