Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 204: 4-97

Answer

$\Delta m=+0.087\ kg/month$

Work Step by Step

From tables 4-1 and 4-2: Energy content of an apple: 70 Cal, Energy content of 100ml of ice-cream: 110 Cal, hence for 200ml: 220 Cal Energy consumption for a 68kg person walking: 432 Cal/h, so for 60kg: 381.18 Cal/h For 20 min of jogging: $\Delta E= (220-70)-381.18\times 1/3\ h = 22.94\ Cal/day=688.2\ Cal/month$ Assuming the mass change would occur entirely in the fat tissue ($e=33.1MJ/kg$): $\Delta m=\Delta E/e $ $\Delta m=+0.087\ kg/month$
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