Answer
$BMI=704.54 \frac{W(lbm)}{H^2(in^2)}$
Work Step by Step
$BMI=W(kg)\div H^2(m²)=W(lbm)\times \frac{1\ kg}{2.2\ lbm}\div (H^2(in²)\times(\frac{1\ m}{39.37\ in})^2)$
$BMI=704.54 \frac{W(lbm)}{H^2(in^2)}$
For the mass to be in the healthy range of $19\leq BMI \leq 25$:
$19.H^2(m^2)\leq W(kg)\leq 25.H^2(m^2)$
$13386.0\times H^2(in^2)\leq W(lbm)\leq 17613.6\times H^2(m^2)$