Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 204: 4-104E

Answer

$BMI=704.54 \frac{W(lbm)}{H^2(in^2)}$

Work Step by Step

$BMI=W(kg)\div H^2(m²)=W(lbm)\times \frac{1\ kg}{2.2\ lbm}\div (H^2(in²)\times(\frac{1\ m}{39.37\ in})^2)$ $BMI=704.54 \frac{W(lbm)}{H^2(in^2)}$ For the mass to be in the healthy range of $19\leq BMI \leq 25$: $19.H^2(m^2)\leq W(kg)\leq 25.H^2(m^2)$ $13386.0\times H^2(in^2)\leq W(lbm)\leq 17613.6\times H^2(m^2)$
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