Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 204: 4-103

Answer

It would take 80 days for the man to lose 5 kg.

Work Step by Step

Total energy consumption for a 68-kg man: $E_c=860+600+540+639+72\times20=4079\ Cal/day$ For a 75-kg man: $E_c=4498.90\ Cal/day$ Since the intake is 4000 Cal/day, $\Delta E=498.9\ Cal/day$ $\Delta t=\Delta m\times e \div \Delta E$ With $e=33.1 MJ/kg, \Delta m = 5\ kg$ So $\Delta t=79.2\ days$ It would take 80 days for the man to lose 5 kg.
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