Answer
$V = 223.8\ V$
Work Step by Step
At the initial state (175 kPa, saturated water):
$v_1=0.001057\ m³/kg,\ h_1=487.01\ kJ/kg$
At the final state (175 kPa, saturated mixture, with 50% quality):
$h_2=1593.56\ kJ/kg$
For this electrically heated, insulated, and agitated constant-pressure stationary closed system, the energy balance reduces to:
$-W_e-W_{sh}=\Delta H$
$W_e=-VI\Delta t$
$W_p=-400kJ$
$\Delta H = m(h_2-h_1)$
$m = \frac{V_1}{v_1} = 4.73\ kg$
$W_e = -4834.39\ kJ$
$V = 223.8\ V$
On the P-v diagram, the process starts at the saturation curve and proceeds in a straight horizontal line to a point below the curve.
