Answer
line 1)
$W_{out} = 510\ Btu$,
$e_2-e_1 = -53.33\ Btu/lbm$
line 2)
$E_2 = 770\ Btu$,
$e_2-e_1 = 44\ Btu/lbm$
line 3)
$E_2 = 900\ Btu$,
$Q_{in} = 560\ Btu$
line 4)
$W_{out} = 0\ Btu$,
$e_2-e_1 = -71.42\ Btu/lbm$
line 5)
$E_2 = 400\ Btu$,
$Q_{in} = -650\ Btu$
Work Step by Step
The balance of energy for a closed system:
$\Delta E = E_2-E_1 = Q_{in} - W_{out}$
Solving for the missing energies:
line 1)
$W_{out} = 510\ Btu$,
$e_2-e_1 = -53.33\ Btu/lbm$
line 2)
$E_2 = 770\ Btu$,
$e_2-e_1 = 44\ Btu/lbm$
line 3)
$E_2-E_1 = m(e_2-e_1) \rightarrow E_2 = 900\ Btu$,
$Q_{in} = 560\ Btu$
line 4)
$W_{out} = 0\ Btu$,
$e_2-e_1 = -71.42\ Btu/lbm$
line 5)
$E_2-E_1 = m(e_2-e_1) \rightarrow E_2 = 400\ Btu$,
$Q_{in} = -650\ Btu$
