Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 198: 4-32

Answer

$q=2133.4\ kJ/kg$

Work Step by Step

Since this process occurs at constant pressure (quasi-equilibrium), the energy balance reduces to: $q=\Delta h$ From the steam table: $h_2 = 604.66\ kJ/kg,\ h_1=2738.1\ kJ/kg$ Therefore: $q=2133.4\ kJ/kg$
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