Answer
a) $51.1^{\circ}C$
Work Step by Step
Knowing that:
$V_{1}=V_{2}$
$m_{1}=m_{2}$
$\frac{T_{1}}{P_{1}}=\frac{T_{2}}{P_{2}}$
$T_{2}=\frac{P_{2}T_{1}}{P_{1}}=\frac{(95+215)kPa*(25+273.15)K}{(95+190)kPa}=324.30K$
$T_{2}=51.15^{\circ}C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 161: 3-142
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