Answer
c) $1.9kW$
Work Step by Step
From table A-5:
$h_{fg}=2256.4\frac{kJ}{kg}$
$m_{evap}=0.5*1kg=0.5kg$
$t=10*60=600s$
$P=\frac{Q}{t}=\frac{mh_{fg}}{t}=\frac{0.5kg*2256.4\frac{kJ}{kg}}{600s}=1.88kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 161: 3-135
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