Answer
a) $71^{\circ}C$
Work Step by Step
Knowing that:
$V_{1}=V_{2}$
$m_{2}=\frac{m_{1}}{2}$
$\frac{m_{1}RT_{1}}{P_{1}}=\frac{m_{2}RT_{2}}{P_{2}}$
$P_{1}=4atm=405.3kPa$
$P_{2}=2.2atm=222.915kPa$
Simplifying and substituting:
$T_{2}=\frac{2T_{1}P_{2}}{P_{1}}=\frac{2*(40+273.15)K*222.915kPa}{405.3kPa}=344.465K$
$T_{2}=71.315^{\circ}C$
