Answer
d) $35kg$
Work Step by Step
From table A-6:
$\upsilon=0.08644\frac{m^3}{kg}$
$m=\frac{V}{\upsilon}=\frac{3m^3}{0.08644\frac{m^3}{kg}}=34.71kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 161: 3-139
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