Answer
$P_{2}=180psia$
$\upsilon_{2}=0.01613\frac{ft^3}{lbm}$
Work Step by Step
$\upsilon_{1}=\frac{V_{1}}{m_{1}}=\frac{2.649ft^3}{lbm}=2.649\frac{ft^3}{lbm}$
As $\upsilon\gt \upsilon_{g}$ is a superheated vapor
From table A-6E:
$P_{1}=180psia=P_{2}$
$T_{2}=100^{\circ}F$
As $T\lt T_{sat}$ is a compressed liquid. From table A-4:
$\upsilon_{2}=0.01613\frac{ft^3}{lbm}$
