Answer
$T_{water}=16.62^{\circ}C$
Work Step by Step
From table A-4 at $T=25^{\circ}C$
$P_{sat}=3.17kPa$
$P_{air}=\phi P_{sat}=0.6*3.17kPa=1.902kPa$
$P_{water}=P_{air}$
Interpolating from table A-4 at $P=1.902kPa$
$T_{water}=16.62^{\circ}C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 158: 3-104
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