Answer
$P_{2}=3.36MPa$
Work Step by Step
Knowing that:
$m_{1}=m_{2}$
$V_{1}=V_{2}$
$P_{2}=P_{1}\frac{T_{2}}{T_{1}}=\frac{1.2MPa*(1750+273.15)K}{(450+273.15)K}=3.36MPa$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 158: 3-111
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