Answer
a) $V_{1}=0.5543\frac{m^3}{s}$
$m_{1}=17.61\frac{kg}{s}$
$\rho_{1}=31.77\frac{kg}{m^3}$
b) $V_{2}=0.4988\frac{m^3}{s}$
Work Step by Step
a) $V_{1}=\frac{NR_{u}T_{1}}{P_{1}}=\frac{0.4\frac{kmol}{s}*8.314\frac{kPam^3}{kmolK}*500K}{3000kPa}=0.5543\frac{m^3}{s}$
$m_{1}=\frac{P_{1}V_{1}}{RT_{1}}=\frac{3000kPa*0.5543\frac{m^3}{s}}{0.1889\frac{kPam^3}{kgK}*500K}=17.61\frac{kg}{s}$
$\rho_{1}=\frac{m_{1}}{V_{1}}=\frac{17.61\frac{kg}{s}}{0.5543\frac{m^3}{s}}=31.77\frac{kg}{m^3}$
b) $V_{2}=\frac{NR_{u}T_{2}}{P_{2}}=\frac{0.4\frac{kmol}{s}*8.314\frac{kPam^3}{kmolK}*450K}{3000kPa}=0.4988\frac{m^3}{s}$
