Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 5 - Newton's Laws of Motion - Problems and Conceptual Exercises - Page 141: 26

Answer

$19.37^{\circ}$

Work Step by Step

We can find the required angle as follows: $a=gsin\theta$ We plug in the known values to obtain: $3.25m/s^2=(9.8m/s^2)sin\theta$ $\implies \theta=sin^{-1}(\frac{3.25m/s^2}{9.8m/s^2})$ $\theta=19.37^{\circ}$
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