Answer
(a) $1036N$
(b) $1036N$
(c) $2590N$
Work Step by Step
(a) The force exerted on the trailer can be determined as
$F=ma$
We plug in the known values to obtain:
$F=(560Kg)(1.85m/s^2)$
$F=1036N$
(b) According to Newton's third law of motion, the net force exerted on the car by the trailer is equal in magnitude but opposite in direction to the force exerted on the trailer by the car, that is $F=1036N$
(c) We can find the required force as
$F=ma$
We plug in the known values to obtain:
$F=(1400Kg)(1.85m/s^2)$
$F=2590N$