Answer
$12m$
Work Step by Step
Using the terms and values on page 248
$\sum\tau = -(2.0m)(6.0\times10^4N)+(4.0m)(6.0\times10^4N)-\frac{(x)(3.0\times10^4N)}{3}=0$
$x=12m$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 256: 57
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