Answer
The iron will shrink by about 0.022%
Work Step by Step
We can solve for the percent change in volume using the following formula:
$\frac{\Delta V}{V_0}=-\frac{1}{B}\Delta P$
$\frac{\Delta V}{V_0}=-\frac{1}{B_{iron}}\Delta P$
$\frac{\Delta V}{V_0}=-\frac{1}{90*10^9N/m^2}(200*1.0*10^5N/m^2-1.1*10^5N/m^2)$
$\frac{\Delta V}{V_0}=-2.2*10^{-4}$
$-2.2*10^{-4}*100=-0.022$%
The iron will shrink by about 0.022%
