Answer
See answers.
Work Step by Step
a. Calculate the stress on the bone.
$$\frac{F}{A}=\frac{3.3\times10^4 \;N}{3.6\times10^{-4}m^2}=9.167\times10^7\;N/m^2$$
This is less than the compressive strength of bone, so the bone does not break.
b. The strain is $\frac{stress}{E}=\frac{9.167\times10^7\;N/m^2}{15\times 10^9 N/m^2}=6.11 \times 10^{-3}$
Use the definition of strain to find the amount by which it is shortened.
$$\Delta \mathcal{l}=\mathcal{l}_o(strain)$$
$$=(22cm)( 6.11 \times 10^{-3})=1.3\times 10^{-3}m$$