Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 256: 45

Answer

$\Delta P=9.0*10^7N/m^2$ or $9.0*10^2atm$

Work Step by Step

We can solve for the change in pressure using the following formula: $\frac{\Delta V}{V_0}=-\frac{1}{B}\Delta P$ $\frac{-.001}{1}=-\frac{1}{B_{iron}}\Delta P$ $\Delta P=-B_{iron}\frac{1}{-.001}$ $\Delta P=-90*10^9N/m^2\frac{-.001}{1}$ $\Delta P=9.0*10^7N/m^2$ or $9.0*10^2atm$
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