Answer
a) See image
b) $F_{Hx}=51.2N$
$F_{Hy}=8.64N$
c) $d=2.35m$
Work Step by Step
b) $F_{Hy}=-22N-g3.8kg+85N\cos(37^o)=8.64N$
$F_{Hx}=85N\sin(37^o)=51.2N$
c) $\sum\tau=-d(22Nsin(53^o))-(2.5m)(38Nsin(53^o))+(5.0m)(85Nsin(16^o))=0$
$d=2.35m$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 254: 27
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